Here’s the rules for every Big Ten BCS tie scenario
SALINE, MICHIGAN OCTOBER 31, 2005 It’s another tight Big Ten football race for the championship and to determine the team that will receive the Big Ten’s automatic BCS bid. Here are the rules:
• If there is a two-way tie, the winner of the game between the two will represent the conference. If the teams did not play each other, it is then based on overall winning percentage.
• If there is still a tie, the most recent team to earn a BCS automatic selection is eliminated.
• If three teams are tied and if one team defeated both of the others, that team is the representative.
• If two of the three teams defeated the third team, that team is eliminated and the remaining two teams revert to the two-team tie procedure.
• If two of the three did not play each other, the BCS representative is determined by winning percentage in the overall schedule. If all three have the same winning percentage, the most recent representative is eliminated and the other two revert to the two-team tie procedure.
• If four or more are tied … if one team defeated each of the other three, then that team is the representative.
• If two of the four teams defeated each of the other two, those two are eliminated and the remaining two revert to the two-team tie procedure.
• If three of the four defeated the fourth, the fourth is eliminated, then it reverts to the three-team tie procedure.
• If two of the four did not play each other, the representative will be determined by overall winning percentage.
• If one of the four teams is eliminated through percentage, the remaining teams revert to three-team tie procedure.
• If all four have the same winning percentage, the most recently Big Ten representative is eliminated and the remaining three must go through the three-team tie procedure.
